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Coding set ‘3=NP-acc’ of Middle English
Coding frames
:
1=3-nom V.subj[1=3] (to+2) 3=1-acc
1=3-nom V.subj[1=3] 2 with+3=1-acc
1=3-nom V.subj[1=3] 2-acc 3=1-acc
1=3-nom V.subj[1=3] 3=1-acc
1=3-nom V.subj[1=3] upon+2 3=1-acc
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